Area of Annulus (Ring)

Learn how to calculate the area of an annulus - the ring-shaped region between two concentric circles.

Intermediate20 minLesson
Printable worksheet

Definition

An annulus (plural: annuli) is the region between two concentric circles - circles that share the same center but have different radii.
To find the area of an annulus:
  1. 1.Calculate the area of the outer circle (larger radius RR)
  2. 2.Calculate the area of the inner circle (smaller radius rr)
  3. 3.Subtract the inner area from the outer area
Aannulus=πR2−πr2=π(R2−r2)A_{\text{annulus}} = \pi R^2 - \pi r^2 = \pi(R^2 - r^2)
Where:
  • RR = radius of the outer circle
  • rr = radius of the inner circle
  • The result is in square units

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What is an annulus?

Worked Examples

Find the area of an annulus with outer radius R=5R = 5 cm and inner radius r=3r = 3 cm.
1

Identify the radii

Outer radius R=5R = 5 cm, Inner radius r=3r = 3 cm → R=5R = 5, r=3r = 3
2

Apply the annulus formula

A=π(R2−r2)A = \pi(R^2 - r^2) → A=π(52−32)A = \pi(5^2 - 3^2)
3

Calculate the squares

52=255^2 = 25 and 32=93^2 = 9 → A=π(25−9)A = \pi(25 - 9)
4

Subtract and multiply by pi

A=π×16=16πA = \pi \times 16 = 16\pi → A=16π≈50.27A = 16\pi \approx 50.27 cm2^2

Common Mistakes

Subtracting radii instead of areas: A=π(R−r)2A = \pi(R - r)^2

Why it's wrong: This calculates the area of a circle with radius (R−r)(R - r), not the ring between two circles.

Correct: Always subtract the areas: A=πR2−πr2=π(R2−r2)A = \pi R^2 - \pi r^2 = \pi(R^2 - r^2)

Confusing diameter with radius

Why it's wrong: Problems often give diameters. Using diameter instead of radius gives an area 4 times too large.

Correct: Always convert diameter to radius first: r=d÷2r = d \div 2

Forgetting that RR must be larger than rr

Why it's wrong: If you accidentally swap the radii, you get a negative area, which is impossible.

Correct: Always identify which circle is outer (larger RR) and which is inner (smaller rr)

Interactive Visual

Area and perimeter

R = 6r = 3

Area84.82

A=π(R2−r2)=π(62−32)≈84.82A = \pi(R^2 - r^2) = \pi(6^2 - 3^2) \approx 84.82

Perimeter56.55

P=2πR+2πr≈56.55P = 2\pi R + 2\pi r \approx 56.55

The ring is the big circle minus the hole: π(R² − r²).

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Practice Problems

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What is an annulus?

Why It Matters

Annuli appear frequently in everyday life and engineering:
  • Pipe cross-sections: Water pipes, garden hoses, and tubes are hollow - their cross-section is an annulus
  • Washers and gaskets: The metal washers used with bolts are annuli
  • CDs and DVDs: The recordable area of a disc is an annulus (the center hole cannot store data)
  • Dartboards: Each scoring ring on a dartboard is an annulus
  • Tree rings: The annual growth rings visible in tree cross-sections
Understanding annulus area helps engineers design pipes, architects plan circular walkways, and scientists measure growth patterns.

Real World Applications

Designing a Circular Walkway

Landscape architects use annulus calculations when designing circular paths around fountains or gardens.

Example:

A circular fountain has radius 4 meters. A walkway 2 meters wide surrounds it. The walkway area is π(62−42)=20π≈62.83\pi(6^2 - 4^2) = 20\pi \approx 62.83 m2^2.

1Try It Yourself

A circular garden has radius 3 meters. You want to add a 1.5-meter wide path around it.

What is the area of the path?

Step 1: Write the mathematical expression

Use the annulus formula with R=4.5R = 4.5 and r=3r = 3:

CD and DVD Storage Capacity

The recordable area of optical discs is an annulus because the center has a hole and non-recordable zone.

Example:

A standard DVD has inner recording radius 24 mm and outer recording radius 58 mm. The data area is π(582−242)=2788π≈8,759\pi(58^2 - 24^2) = 2788\pi \approx 8,759 mm2^2.

2Try It Yourself

A mini-CD has outer recording radius 40 mm and inner recording radius 22 mm.

What is the recordable area?

Step 1: Write the mathematical expression

Calculate π(402−222)\pi(40^2 - 22^2):

Key Takeaways

  • 1An annulus is the region between two concentric circles (same center, different radii)
  • 2Area formula: A=π(R2−r2)A = \pi(R^2 - r^2) where RR is outer radius and rr is inner radius
  • 3This equals outer circle area minus inner circle area: πR2−πr2\pi R^2 - \pi r^2
  • 4Always identify which radius is larger before calculating
  • 5Convert diameters to radii before using the formula

Frequently Asked Questions

Divide each diameter by 2 to get the radii. If outer diameter is DD and inner diameter is dd, then A=π((D2)2−(d2)2)=π4(D2−d2)A = \pi\left(\left(\frac{D}{2}\right)^2 - \left(\frac{d}{2}\right)^2\right) = \frac{\pi}{4}(D^2 - d^2).
Divide each diameter by 2 to get the radii. If outer diameter is DD and inner diameter is dd, then A=π((D2)2−(d2)2)=π4(D2−d2)A = \pi\left(\left(\frac{D}{2}\right)^2 - \left(\frac{d}{2}\right)^2\right) = \frac{\pi}{4}(D^2 - d^2).
Yes! The formula works whether there's an actual inner circle or just a hole. The annulus is the ring-shaped region regardless of what's inside.
They're the same shape! 'Annulus' is the mathematical term, while 'washer' is the common name for the physical object (like the metal rings used with bolts).

Glossary

Annulus
A ring-shaped region between two concentric circles
Concentric circles
Circles that share the same center point but have different radii
Outer radius (R)
The radius of the larger circle that forms the outside edge of the annulus
Inner radius (r)
The radius of the smaller circle that forms the inside edge (hole) of the annulus
Today's challengeOne problem, three tries

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