Volume of Pyramids
Square Pyramid
A pyramid has a square base with sides of $6$ cm and a perpendicular height of $10$ cm. What is its volume?
Find the base area: $B = s^2 = 6^2 = 36$ = $B = 36$ cm²
Multiply by the height: $B \times h = 36 \times 10 = 360$ = $360$ (this would be the prism)
Take one third: $V = \frac{1}{3} \times 360 = 120$ = $V = 120$ cm³
Answer: The volume is $120$ cm³.
Rectangular Base
A pyramid has a rectangular base of $8$ m by $6$ m and a height of $10$ m. Find its volume.
Find the base area: $B = l \times w = 8 \times 6 = 48$ = $B = 48$ m²
Multiply by the height: $48 \times 10 = 480$ = $480$
Divide by 3: $V = 480 \div 3 = 160$ = $V = 160$ m³
Answer: The volume is $160$ m³.
Triangular Base
The base of a pyramid is a triangle with a base of $6$ cm and a height of $4$ cm. The pyramid is $9$ cm tall. What is its volume?
Find the area of the base triangle: $B = \frac{1}{2} \times 6 \times 4 = 12$ = $B = 12$ cm²
Multiply by the pyramid's height: $12 \times 9 = 108$ = $108$
Take one third: $V = 108 \div 3 = 36$ = $V = 36$ cm³
Answer: The volume is $36$ cm³. Notice the two different heights: $4$ cm belongs to the base triangle, $9$ cm is the height of the pyramid.
Finding the Height From the Volume
A pyramid with a square base of side $9$ m has a volume of $324$ m³. How tall is it?
Find the base area: $B = 9^2 = 81$ = $B = 81$ m²
Multiply both sides of $V = \frac{1}{3}Bh$ by 3: $3V = Bh$, so $3 \times 324 = 972$ = $Bh = 972$
Divide by the base area: $h = \frac{3V}{B} = 972 \div 81 = 12$ = $h = 12$ m
Answer: The pyramid is $12$ m tall.
Using the Slant Height
A square pyramid has base sides of $10$ cm and a slant height of $13$ cm. Find its volume.
Draw the right triangle inside the pyramid: Legs: $h$ and half the side, $10 \div 2 = 5$. Hypotenuse: the slant height $13$ = $h^2 + 5^2 = 13^2$
Use Pythagoras to find h: $h^2 = 169 - 25 = 144$, so $h = \sqrt{144}$ = $h = 12$ cm
Find the base area: $B = 10^2 = 100$ = $B = 100$ cm²
Apply the volume formula: $V = \frac{1}{3} \times 100 \times 12 = \frac{1200}{3} = 400$ = $V = 400$ cm³
Answer: The volume is $400$ cm³. Using $13$ instead of $12$ would give a wrong answer of about $433$ cm³.
Mistake: Forgetting the $\frac{1}{3}$ and calculating $V = Bh$
Why: $Bh$ is the volume of the prism with the same base and height. A pyramid fills only one third of it.
Correct: Always finish with $\div 3$: a square pyramid with $s = 6$ and $h = 10$ has $V = 360 \div 3 = 120$, not $360$.
Mistake: Using the slant height instead of the perpendicular height
Why: The slant height runs along a sloping face, so it is longer than the true height. Using it makes the volume too big.
Correct: Use the height that meets the base at a right angle. If only the slant height is given, find $h$ with $h^2 + \left(\frac{s}{2}\right)^2 = l^2$.
Mistake: Putting a side length in place of the base area
Why: $B$ is an area, not a length. Writing $\frac{1}{3} \times 6 \times 10$ for a square base of side $6$ leaves out a whole factor.
Correct: Compute $B$ first: $B = 6^2 = 36$, then $V = \frac{1}{3} \times 36 \times 10 = 120$.
Mistake: Forgetting the $\frac{1}{2}$ in a triangular base
Why: The area of a triangle is half of base times height, so $b \times h_b$ alone is twice too big.
Correct: For a triangular base with $b = 6$ and $h_b = 4$: $B = \frac{1}{2} \times 6 \times 4 = 12$, not $24$.
The Great Pyramid of Giza
Historians estimate how much stone the Egyptians moved by treating the Great Pyramid as a square pyramid.
When it was built, the pyramid had a square base of about $230$ m per side and was about $147$ m tall.
Pyramid Tents
Camping gear makers give the inside volume of tents so you can compare how roomy they are.
A tent with a square floor of $2$ m by $2$ m and a center pole of $1.5$ m is a square pyramid.
Pyramid Roofs
Heating engineers need the volume of the air space under a roof to size a heater or a ventilation fan.
A pyramid roof (hip roof that ends in one point) sits on a house with a rectangular floor plan.
The volume of any pyramid is $V = \frac{1}{3}Bh$, where $B$ is the base area and $h$ the perpendicular height
Find $B$ first: $s^2$ for a square, $l \times w$ for a rectangle, $\frac{1}{2} \times b \times h_b$ for a triangle
A pyramid holds exactly one third of the prism with the same base and height
Use the perpendicular height, not the slant height; if needed, find it with $h^2 + \left(\frac{s}{2}\right)^2 = l^2$
To find the height from the volume, use $h = \frac{3V}{B}$
Volume is always in cubic units (cm³, m³)
Q: Why is there a $\frac{1}{3}$ in the formula?
A: A pyramid narrows to a point, so it holds less than a prism with the same base and height. Experiments with sand or water show that exactly three pyramids fill the prism. It can also be proven: a cube can be cut into three identical pyramids that each have one face of the cube as their base.
Q: Is the cone formula related?
A: Yes. A cone is like a pyramid with a circular base, so $V = \frac{1}{3}Bh$ with $B = \pi r^2$ gives $V = \frac{1}{3}\pi r^2 h$, the same one-third rule.
Q: Does the formula work if the apex is not above the center of the base?
A: Yes. A leaning (oblique) pyramid has the same volume as a straight one with the same base and the same perpendicular height. Only measure $h$ straight up from the level of the base to the apex.
Q: What if the base has 5 or 6 sides?
A: The formula $V = \frac{1}{3}Bh$ works for any base. The only change is how you find $B$: split the polygon into triangles or use its area formula, then multiply by $h$ and divide by 3.
Volume of Pyramids
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Volume of Pyramids
Learn how to find the volume of square, rectangular and triangular pyramids with V = (1/3)Bh, and how to get the height from the slant height.