Circles in Standard Form

Learn how to write and interpret the equation of a circle in standard form.

Advanced25 minLesson
Printable worksheet

Definition

The standard form of a circle's equation is:
(x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2
Where:
  • (h,k)(h, k) is the center of the circle
  • rr is the radius (always positive)
Key insight: Every point (x,y)(x, y) on the circle is exactly rr units from the center.
Special case: When the center is at the origin (0,0)(0, 0):
x2+y2=r2x^2 + y^2 = r^2

Try it now

What is the center of the circle (x−4)2+(y−7)2=16(x - 4)^2 + (y - 7)^2 = 16?

Worked Examples

Find the center and radius of the circle: (x−3)2+(y+2)2=25(x - 3)^2 + (y + 2)^2 = 25
1

Compare to standard form

Standard form: (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2 → Match the pattern
2

Identify h (x-coordinate of center)

(x−3)2(x - 3)^2 means h=3h = 3
3

Identify k (y-coordinate of center)

(y+2)2=(y−(−2))2(y + 2)^2 = (y - (-2))^2 means k=−2k = -2
4

Find the radius

r2=25r^2 = 25, so r=25=5r = \sqrt{25} = 5 → r=5r = 5

Common Mistakes

Confusing the signs in (y+2)2(y + 2)^2

Why it's wrong: Standard form uses subtraction: (y−k)2(y - k)^2. If you see (y+2)2(y + 2)^2, this equals (y−(−2))2(y - (-2))^2, so k=−2k = -2, not +2+2.

Correct: Always rewrite as subtraction: (y+2)2=(y−(−2))2(y + 2)^2 = (y - (-2))^2, therefore k=−2k = -2.

Using r2r^2 as the radius instead of rr

Why it's wrong: The equation gives r2r^2, not rr. You must take the square root.

Correct: If the equation shows =49= 49, then r2=49r^2 = 49 and r=7r = 7 (not 49).

Forgetting to square the radius when writing equations

Why it's wrong: When given radius r=4r = 4, students write =4= 4 instead of =16= 16.

Correct: Always square the radius: if r=4r = 4, write r2=16r^2 = 16 in the equation.

Interactive Visual

Function graph

-10-50510-10-50510xyC(3, -2)
  • r² = 25
(x − h)² + (y − k)² = r²
  • Center: (3, -2)

Function graph

-4-202468-505xyC(2, -1)(5, 3)
(x − 2)² + (y + 1)² = 25
  • Center: (2, -1)
  • Length of (2, -1) – (5, 3): d = 5

Interactive Sandbox

Interactive Grapher

-10-50510-10-50510xy

Tap or hover over the graph to read off values.

Try these examples:

y = -2 + sqrt(25 - (x - 3)^2)

y = -2 - sqrt(25 - (x - 3)^2)

Expression Calculator

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Practice Problems

15 problems
Problem 1 of 15
Easy
What is the center of the circle (x−4)2+(y−7)2=16(x - 4)^2 + (y - 7)^2 = 16?

Why It Matters

Circle equations appear throughout mathematics and real-world applications:
  • GPS and Navigation: Cell phone towers use circles to triangulate your position
  • Engineering: Designing gears, wheels, and circular components
  • Astronomy: Modeling planetary orbits (simplified as circles)
  • Architecture: Planning circular buildings, domes, and arenas
  • Physics: Describing circular motion and wave propagation
Understanding the standard form lets you quickly identify a circle's key properties from its equation.

Real World Applications

GPS Triangulation

Cell towers and GPS satellites use circles to locate your position. Each tower knows its distance to your phone, creating a circle of possible locations.

Example:

A cell tower at position (2,3)(2, 3) km detects your phone at distance 55 km. Your possible locations form the circle (x−2)2+(y−3)2=25(x - 2)^2 + (y - 3)^2 = 25.

1Try It Yourself

A rescue beacon is detected 10 km from a station at coordinates (0,0)(0, 0).

What equation describes all possible locations of the beacon?

Step 1: Write the mathematical expression

Center at origin, radius 10:

Circular Race Tracks

Architects design circular tracks using circle equations to ensure the track has the correct dimensions.

Example:

A running track has an inner edge with center at the origin and radius 3030 meters: x2+y2=900x^2 + y^2 = 900. The outer edge has radius 3535 meters: x2+y2=1225x^2 + y^2 = 1225.

2Try It Yourself

A circular fountain is designed with center at (5,5)(5, 5) meters from a corner and radius 33 meters.

Write the equation for the fountain's edge.

Step 1: Write the mathematical expression

Standard form equation:

Key Takeaways

  • 1Standard form of a circle: (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2
  • 2(h,k)(h, k) is the center, rr is the radius
  • 3Watch the signs: (y+2)2(y + 2)^2 means k=−2k = -2
  • 4The right side is r2r^2, not rr - take the square root to find the radius
  • 5Circle centered at origin: x2+y2=r2x^2 + y^2 = r^2

Frequently Asked Questions

The standard form uses subtraction because it's based on the distance formula. The expression (x−h)2+(y−k)2(x - h)^2 + (y - k)^2 calculates the squared distance from any point (x,y)(x, y) to the center (h,k)(h, k).
The standard form uses subtraction because it's based on the distance formula. The expression (x−h)2+(y−k)2(x - h)^2 + (y - k)^2 calculates the squared distance from any point (x,y)(x, y) to the center (h,k)(h, k).
No. The radius is always positive because it represents a distance. If r2=25r^2 = 25, then r=5r = 5 (we take the positive square root).
Some equations need to be rewritten. For example, x2+y2−6x+4y=12x^2 + y^2 - 6x + 4y = 12 can be converted to standard form by completing the square. This is covered in the 'Converting to Standard Form' lesson.

Glossary

Standard form
The equation (x−h)2+(y−k)2=r2(x - h)^2 + (y - k)^2 = r^2 where (h,k)(h, k) is the center and rr is the radius
Center
The fixed point (h,k)(h, k) that is equidistant from all points on the circle
Radius
The constant distance rr from the center to any point on the circle
Conic section
A curve formed by intersecting a plane with a cone - circles, ellipses, parabolas, and hyperbolas
Today's challengeOne problem, three tries

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