Mathorio
Answer key
Introduction to Hyperbolas
Show your work for each problem.
- 1.Which equation represents a hyperbola?
- a)
- b)
- c)
- d)
Answer:
is a hyperbola because it has subtraction between the squared terms. The first option is an ellipse (addition), the third is a circle, and the fourth is a parabola.
- 2.The hyperbola opens in which direction?
- a)Up and down
- b)Diagonally
- c)Left and right
- d)It does not open
Answer: Left and right
Since is the positive term (comes first and has no negative sign), this is a horizontal hyperbola that opens left and right.
- 3.For the hyperbola , what is the value of ?
Answer: 5
In the standard form, is always under the positive term. Here , so .
- 4.For the hyperbola , what is the value of ?
Answer: 4
In the standard form, is under the negative term. Here , so .
- 5.What is the correct formula to find (focal distance) in a hyperbola?
- a)
- b)
- c)
- d)
Answer:
For hyperbolas, use . This is different from ellipses where . In hyperbolas, because the foci are farther from the center than the vertices.
- 6.For the hyperbola , calculate the value of .
Answer: 5
, so .
- 7.Find the vertices of the hyperbola .
Answer: (-6, 0) and (6, 0)
- Is this a horizontal or vertical hyperbola? horizontal
- What is ? 36
- What is ? 6
- For a horizontal hyperbola, vertices are at . What are the vertices? (-6, 0) and (6, 0)
- 8.Find the foci of the hyperbola .
Answer: (0, -5) and (0, 5)
- Is this a horizontal or vertical hyperbola? vertical
- What are and ? a^2 = 9, b^2 = 16
- Calculate . 25
- What is ? 5
- For a vertical hyperbola, foci are at . What are the foci? (0, -5) and (0, 5)
- 9.What are the asymptotes of the hyperbola ?
- a)
- b)
- c)
- d)
Answer:
This is a horizontal hyperbola with () and (). For horizontal hyperbolas, asymptotes are .
- 10.Find the asymptotes of the hyperbola .
Answer: y = (5/4)x and y = -(5/4)x
- Is this a horizontal or vertical hyperbola? vertical
- What is ? 5
- What is ? 4
- For vertical hyperbolas, asymptotes are . What is the slope? 5/4
- 11.Find the center, vertices, foci, and asymptotes of .
Answer: Center (0,0), Vertices (+-7,0), Foci (+-sqrt(73),0), Asymptotes y = +-sqrt(24)/7 x
- What is the center? (0, 0)
- What is ? 7
- What are the vertices? (-7, 0) and (7, 0)
- Calculate . 73
- What are the foci? (+-sqrt(73), 0)
- What is ? sqrt(24)
- What are the asymptotes? y = +-sqrt(24)/7 x
- 12.A hyperbola has vertices at and , and foci at and . What is the value of ?
Answer: 8
Vertices at means . Foci at means . Using : , so and .
- 13.The defining property of a hyperbola is that for any point on the curve:
- a)The sum of distances to the foci is constant
- b)The difference of distances to the foci is constant
- c)The product of distances to the foci is constant
- d)The ratio of distances to the foci is constant
Answer: The difference of distances to the foci is constant
A hyperbola is defined by the constant absolute difference of distances: . An ellipse has constant sum. This is the key distinction.
- 14.Write the equation of a hyperbola with vertices at and foci at .
Answer: x^2/25 - y^2/144 = 1
- Is this a horizontal or vertical hyperbola? horizontal
- What is ? 5
- What is ? 13
- Use to find . 144
- Write the equation. x^2/25 - y^2/144 = 1
- 15.GPS systems determine location using the intersection of hyperbolas. Why are hyperbolas used instead of circles?
- a)Circles are too difficult to calculate
- b)GPS measures the difference in arrival times between satellite signals
- c)GPS measures exact distances from satellites
- d)Hyperbolas are more accurate than circles
Answer: GPS measures the difference in arrival times between satellite signals
GPS receivers measure the time difference between signals from two satellites. This time difference corresponds to a difference in distances, which defines a hyperbola. The intersection of multiple hyperbolas pinpoints your location.