How many points do I need to sketch the graph?

Four or five are enough: the y-intercept, one or two points on each side, and the asymptote. A table from $x = -2$ to $x = 3$ shows both the flat side and the steep side.

Why do $y = 2^x$ and $y = (0.5)^x$ look like mirror images?

Because $(0.5)^x = 2^{-x}$. The value of $(0.5)^x$ at $x = 3$ equals the value of $2^x$ at $x = -3$, so every point $(x, y)$ of one graph has the partner $(-x, y)$ on the other.

Does a horizontal shift change the asymptote?

No. Shifting left or right slides the curve along the asymptote, so it stays at $y = k$. Only the vertical shift $k$ moves the asymptote. A horizontal shift does change the y-intercept, though.

Teacher Resources

Graphing Exponential Functions

Q: Does an exponential graph ever touch its asymptote?

No. For $y = a \cdot b^x + k$, the term $a \cdot b^x$ is never 0, so $y$ is never equal to $k$. The curve gets as close as you like, which is why the range is $y > k$ or $y < k$ and never includes $k$.

Plot y = a·b^x from a table of values, read its intercept and asymptote, and see how shifts, reflections and stretches move the graph.

Advanced30 minLesson

Printable worksheet

Definition

To graph an exponential function

f(x) = a \cdot b^x

(with

b > 0

and

b \neq 1

), make a table of values, plot the points and join them with a smooth curve that bends toward a horizontal asymptote.

The two basic shapes (here with

a = 1

$x$	$-2$	$-1$	$0$	$1$	$2$	$3$
$2^x$	$0.25$	$0.5$	$1$	$2$	$4$	$8$
$(0.5)^x$	$4$	$2$	$1$	$0.5$	$0.25$	$0.125$

If $b > 1$ , the graph rises from left to right: almost flat near the x-axis on the left, steeper and steeper on the right.
If $0 < b < 1$ , the graph falls from left to right: steep on the left, almost flat near the x-axis on the right.

**Key features of

y = a \cdot b^x

:**

y-intercept: $(0, a)$ , because $b^0 = 1$
Horizontal asymptote: $y = 0$ (the x-axis); the curve gets closer and closer but never touches it
Domain: all real numbers
Range: $y > 0$ when $a > 0$ , and $y < 0$ when $a < 0$

Transformations:

y = a \cdot b^{x-h} + k

$h$ shifts the graph $h$ units right (left when $h$ is negative)
$k$ shifts the graph $k$ units up (down when $k$ is negative) and moves the asymptote to $y = k$
$a < 0$ reflects the graph in the x-axis (before the shift), so it lies below its asymptote
a factor $a$ with $\lvert a \rvert > 1$ stretches the graph vertically, $0 < \lvert a \rvert < 1$ compresses it
Range of the transformed graph: $y > k$ when $a > 0$ , and $y < k$ when $a < 0$

Try it now

What is the horizontal asymptote of

y = 2^x - 7

? Enter the number

k

y = k

Worked Examples

Graph $y = 3 \cdot 2^x$ for $x = -2$ to $x = 3$ . State the y-intercept, the asymptote, the domain and the range.

Compute the values for negative $x$

$3 \cdot 2^{-2} = 3 \cdot \frac{1}{4} = 0.75$ and $3 \cdot 2^{-1} = 3 \cdot \frac{1}{2} = 1.5$ → Points $(-2, 0.75)$ and $(-1, 1.5)$

Compute the values for $x = 0$ to $3$

$3 \cdot 2^0 = 3$ , $3 \cdot 2^1 = 6$ , $3 \cdot 2^2 = 12$ , $3 \cdot 2^3 = 24$ → Points $(0, 3)$ , $(1, 6)$ , $(2, 12)$ , $(3, 24)$

Plot and join the points

Each step to the right doubles $y$ ; each step to the left halves it → A rising curve, flat on the left and steep on the right

Read the key features

$a = 3$ gives the y-intercept; nothing is added, so $k = 0$ → y-intercept $(0, 3)$ , asymptote $y = 0$ , domain all real numbers, range $y > 0$

Answer: The graph passes through $(-2, 0.75)$ , $(-1, 1.5)$ , $(0, 3)$ , $(1, 6)$ , $(2, 12)$ , $(3, 24)$ . It rises from left to right, crosses the y-axis at $(0, 3)$ , approaches the asymptote $y = 0$ on the left, has domain all real numbers and range $y > 0$ .

Common Mistakes

Keeping the asymptote at $y = 0$ after a vertical shift, for example for $y = 2^x + 3$

Why it's wrong: Adding $k$ moves every point up by $k$ , including the level the curve approaches. The graph of $y = 2^x + 3$ never goes below 3.

Correct: For $y = a \cdot b^{x-h} + k$ the asymptote is $y = k$ . For $y = 2^x + 3$ it is $y = 3$ and the range is $y > 3$ .

Shifting the wrong way: thinking $y = 2^{x-3}$ moves the graph 3 units left

Why it's wrong: In $x - 3$ you need a larger $x$ to get the same exponent as before. The point $(0, 1)$ of $y = 2^x$ is now at $(3, 1)$ .

Correct: $x - h$ shifts right by $h$ , $x + h$ shifts left by $h$ . $y = 2^{x-3}$ moves right 3, $y = 2^{x+3}$ moves left 3.

Reading the y-intercept as $a$ (or $a + k$ ) when the graph is also shifted sideways

Why it's wrong: The y-intercept is $(0, a)$ only for $y = a \cdot b^x$ . After a horizontal shift the exponent at $x = 0$ is no longer 0.

Correct: Always substitute $x = 0$ . For $y = 2^{x-1} + 3$ : $2^{-1} + 3 = 3.5$ , not 1 and not 4.

Treating $-2^x$ as $(-2)^x$

Why it's wrong: Powers are computed before the minus sign, so $-2^x = -(2^x)$ . The base is 2, not $-2$ , and $(-2)^x$ is not even an exponential function.

Correct: $-2^x$ is the graph of $2^x$ reflected in the x-axis: at $x = 2$ it gives $-4$ , while $(-2)^2 = 4$ .

Interactive Visual

Function graph

a = 3b = 2h = 0k = 0

Tap or hover over the graph to read off values.

y = a·b^(x − h) + kAsymptote

Table of values

x	-2	-1	0	1	2	3
y	0.75	1.5	3	6	12	24

Function graph

Tap or hover over the graph to read off values.

Tap a name to show or hide its graph.

Asymptote

Table of values

x	-2	-1	0	1	2	3
2^x	0.25	0.5	1	2	4	8
0.5^x	4	2	1	0.5	0.25	0.125

Interactive Sandbox

Expression Calculator

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Practice Problems

18 problems

Problem 1 of 18

Easy

What is the y-intercept of the graph of $y = 5 \cdot 3^x$ ?

Why It Matters

A graph shows at a glance what a formula hides. Once you can sketch an exponential graph, you can:

Recognize exponential data: when a chart of followers, cells or savings curves upward faster and faster, a table of values tells you whether it really multiplies by the same factor each step.
Read the starting value and the floor: the y-intercept is where the quantity starts, and the asymptote $y = k$ is the level it can approach but never cross, such as a baseline that is always there.
Check a model quickly: a sketch tells you immediately if a formula rises or falls, where it crosses the axes and which values are impossible (outside the range).
Build a model from data: two points like $(0, 3)$ and $(1, 6)$ are enough to find $a$ and $b$ and predict the next values.

These skills come back later in this topic in decay, half-life, continuous growth and exponential equations, and after that in logarithms.

Real World Applications

Reading Lab Data on a Graph

Biologists plot cell counts over time. If the points lie on an exponential curve, two readings are enough to write the model and predict later counts.

Example:

A culture counted 100 cells at the start and 200 cells one hour later follows $y = 100 \cdot 2^x$ , so after 4 hours the curve is at $100 \cdot 16 = 1600$ cells.

1Try It Yourself

A cell culture has 200 cells at $x = 0$ hours and 600 cells at $x = 1$ hour, and the graph is exponential: $y = a \cdot b^x$ .

How many cells does the model predict at $x = 3$ hours?

Step 1: Write the mathematical expression

Find $a$ and $b$ , then evaluate $a \cdot b^3$ :

Video Views with a Baseline

Some quantities have a part that grows exponentially on top of a constant part. The constant part is the vertical shift $k$, and on the graph it is the asymptote.

Example:

A video gets a steady 100 views a day from search, plus a shared part that doubles every day: $V(t) = 25 \cdot 2^t + 100$ . Going back in time the shared part shrinks toward 0, so the graph approaches $V = 100$ .

2Try It Yourself

Daily views follow $V(t) = 25 \cdot 2^t + 100$ , where $t$ is the number of days since the video was shared.

How many views does the video get on day $t = 4$ ?

Step 1: Write the mathematical expression

Evaluate $25 \cdot 2^4 + 100$ :

Folding Paper

Each fold doubles the thickness of a sheet of paper, so the thickness after $n$ folds is an exponential function whose graph climbs faster and faster.

Example:

A sheet 0.1 mm thick has thickness $T(n) = 0.1 \cdot 2^n$ mm. After 7 folds that is $0.1 \cdot 128 = 12.8$ mm.

3Try It Yourself

A sheet of paper is 0.1 mm thick, and its thickness after $n$ folds is $T(n) = 0.1 \cdot 2^n$ mm.

After how many folds is the stack thicker than 1 mm for the first time?

Step 1: Write the mathematical expression

Make a table of $0.1 \cdot 2^n$ and look for the first value above 1:

Key Takeaways

1To graph $y = a \cdot b^x$ , make a table (for example $x = -2$ to $3$ ), plot the points and join them with a smooth curve
2If $b > 1$ the graph rises from left to right; if $0 < b < 1$ it falls; $y = b^x$ and $y = (1/b)^x$ are mirror images in the y-axis
3For $y = a \cdot b^x$ : y-intercept $(0, a)$ , asymptote $y = 0$ , domain all real numbers, range $y > 0$ when $a > 0$
4In $y = a \cdot b^{x-h} + k$ : $h$ shifts right, $k$ shifts up and moves the asymptote to $y = k$ , and $a < 0$ puts the graph below the asymptote
5After a shift, find the y-intercept by substituting $x = 0$ ; the range is $y > k$ or $y < k$
6Two points find the equation: $a$ is the value at $x = 0$ , and dividing the y-values gives a power of $b$

Frequently Asked Questions

No. For

y = a \cdot b^x + k

, the term

a \cdot b^x

is never 0, so

y

is never equal to

k

. The curve gets as close as you like, which is why the range is

y > k

y < k

and never includes

k

Glossary

Table of values: A list of chosen $x$ values with the matching $y$ values, used to plot points of a graph
Horizontal asymptote: A horizontal line $y = k$ that the graph approaches more and more closely but never reaches
y-intercept: The point where the graph crosses the y-axis, found by substituting $x = 0$
Domain: All $x$ values a function accepts; for every exponential function it is all real numbers
Range: All $y$ values the function reaches; for $y = a \cdot b^x + k$ it is $y > k$ (if $a > 0$ ) or $y < k$ (if $a < 0$ )
Transformation: A shift, reflection or stretch that moves or reshapes a graph, described by $h$ , $k$ and $a$ in $y = a \cdot b^{x-h} + k$

Formula Card

Exponential function

y = a \cdot b^x

y-intercept $(0, a)$, asymptote $y = 0$, rises if $b > 1$, falls if $0 < b < 1$

Transformed form

y = a \cdot b^{x-h} + k

Shift right $h$, up $k$; asymptote $y = k$; range $y > k$ if $a > 0$, $y < k$ if $a < 0$

Mirror image

(1/b)^x = b^{-x}

The graphs of $b^x$ and $(1/b)^x$ are reflections of each other in the y-axis

Base from two points

b^{x_2 - x_1} = \frac{y_2}{y_1}

Divide the y-values of two points on $y = a \cdot b^x$ to get a power of $b$

Graphing Exponential Functions

Definition

Worked Examples

Common Mistakes

Interactive Visual

Function graph

Table of values

Function graph

Table of values

Interactive Sandbox

Expression Calculator

History

Practice Problems

Why It Matters

Real World Applications

Reading Lab Data on a Graph

Video Views with a Baseline

Folding Paper

Key Takeaways

Frequently Asked Questions

Glossary

Formula Card

Exponential function

Transformed form

Mirror image

Base from two points

More in This Topic

Introduction to Exponential Functions

Exponential Growth

Exponential Decay

The Natural Base e