Graphing the Sine Function
Plotting the Basic Sine Curve
Graph $y = \sin(x)$ for $0 \leq x \leq 2\pi$
Create a table of key values: Identify the five key points: $x = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi$ = Key x-values identified
Calculate the y-values: $\sin(0)=0$, $\sin(\frac{\pi}{2})=1$, $\sin(\pi)=0$, $\sin(\frac{3\pi}{2})=-1$, $\sin(2\pi)=0$ = Points: $(0,0)$, $(\frac{\pi}{2},1)$, $(\pi,0)$, $(\frac{3\pi}{2},-1)$, $(2\pi,0)$
Plot the points: Mark each point on the coordinate plane = Five points plotted
Connect with a smooth curve: Draw a smooth wave connecting all points = One complete sine wave
Answer: The graph starts at the origin, rises to a maximum of 1, returns to 0, falls to a minimum of -1, and returns to 0 to complete one cycle.
Graphing with Amplitude Change
Graph $y = 3\sin(x)$ and describe how it differs from $y = \sin(x)$
Identify the amplitude: The coefficient 3 in front of sin is the amplitude = Amplitude = 3
Calculate the new key points: Multiply all y-values by 3: $(0,0)$, $(\frac{\pi}{2},3)$, $(\pi,0)$, $(\frac{3\pi}{2},-3)$, $(2\pi,0)$ = Key points with amplitude 3
Note the range: The function oscillates between $-3$ and $3$ = Range: $[-3, 3]$
Draw the graph: The wave is stretched vertically, 3 times taller = Graph complete
Answer: The graph of $y = 3\sin(x)$ is a vertical stretch of the basic sine curve. It oscillates between $-3$ and $3$ instead of $-1$ and $1$, while the period remains $2\pi$.
Graphing with Period Change
Graph $y = \sin(2x)$ and find its period
Find the period formula: Period $= \frac{2\pi}{|B|}$ where $B$ is the coefficient of $x$ = Period formula identified
Calculate the new period: Period $= \frac{2\pi}{2} = \pi$ = Period = $\pi$
Find key points for one period: Divide $[0, \pi]$ into four equal parts: $0, \frac{\pi}{4}, \frac{\pi}{2}, \frac{3\pi}{4}, \pi$ = Key x-values identified
Calculate y-values: $\sin(0)=0$, $\sin(\frac{\pi}{2})=1$, $\sin(\pi)=0$, $\sin(\frac{3\pi}{2})=-1$, $\sin(2\pi)=0$ = Points: $(0,0)$, $(\frac{\pi}{4},1)$, $(\frac{\pi}{2},0)$, $(\frac{3\pi}{4},-1)$, $(\pi,0)$
Answer: The graph of $y = \sin(2x)$ completes one full cycle in $\pi$ radians instead of $2\pi$. It is horizontally compressed, completing two cycles in the same interval where $\sin(x)$ completes one.
General Sinusoidal Function
Describe the graph of $y = 2\sin(x - \frac{\pi}{4}) + 1$
Identify the amplitude: The coefficient of sine is 2 = Amplitude = 2
Find the period: The coefficient of $x$ is 1, so Period $= \frac{2\pi}{1} = 2\pi$ = Period = $2\pi$
Find the phase shift: The expression $(x - \frac{\pi}{4})$ shifts right by $\frac{\pi}{4}$ = Phase shift = $\frac{\pi}{4}$ right
Find the vertical shift: The $+1$ at the end shifts the midline up by 1 = Vertical shift = 1 up
Determine the range: Midline at $y=1$, amplitude 2, so range is $[1-2, 1+2] = [-1, 3]$ = Range: $[-1, 3]$
Answer: The graph has amplitude 2, period $2\pi$, is shifted right by $\frac{\pi}{4}$, and shifted up by 1. It oscillates between $-1$ and $3$ with its midline at $y = 1$.
Mistake: Confusing degrees and radians on the x-axis
Why: The standard sine graph uses radians. $\pi \approx 3.14$ radians equals 180 degrees.
Correct: Always check if your calculator and graph are in the same mode. For calculus and higher math, radians are standard.
Mistake: Getting the phase shift direction wrong
Why: In $y = \sin(x - c)$, the shift is to the RIGHT, not left. The minus inside creates opposite behavior.
Correct: $y = \sin(x - \frac{\pi}{2})$ shifts RIGHT by $\frac{\pi}{2}$. $y = \sin(x + \frac{\pi}{2})$ shifts LEFT by $\frac{\pi}{2}$.
Mistake: Confusing amplitude with range
Why: Amplitude is the distance from the midline to the peak, not the total height.
Correct: For $y = 3\sin(x)$, amplitude is 3, but the total height (range) is 6 (from $-3$ to $3$).
Mistake: Forgetting that the coefficient of $x$ affects period, not amplitude
Why: In $y = \sin(Bx)$, $B$ compresses or stretches horizontally, changing the period.
Correct: Period $= \frac{2\pi}{|B|}$. Larger $B$ means shorter period (faster oscillation).
Sound Waves and Music
Pure musical tones are sine waves. A tuning fork vibrates at 440 Hz (A note), creating a sine wave in air pressure.
The equation $y = \sin(880\pi t)$ models a 440 Hz sound wave, where $t$ is time in seconds.
Electrical Engineering - AC Current
Household electricity uses alternating current that follows a sine wave pattern.
European outlets provide 230V at 50 Hz: $V(t) = 325\sin(100\pi t)$ where the peak voltage is about 325V.
Ocean Tides
Tidal heights follow a roughly sinusoidal pattern due to the moon's gravitational pull.
If high tide is at 6 AM with height 3 meters and low tide is at 12 PM with height 1 meter, the tide can be modeled with a sine function.
The sine function $y = \sin(x)$ creates a smooth wave oscillating between $-1$ and $1$
Key points occur at $x = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi$ (values: $0, 1, 0, -1, 0$)
The period of the basic sine function is $2\pi$ (one complete cycle)
In $y = A\sin(Bx - C) + D$: $|A|$ = amplitude, $\frac{2\pi}{|B|}$ = period, $\frac{C}{B}$ = phase shift, $D$ = vertical shift
Amplitude is the distance from the midline to the peak, not the total height
Q: Why does the sine function start at zero?
A: On the unit circle, sine represents the y-coordinate. At angle 0 (pointing right on the x-axis), the y-coordinate is 0. This is why $\sin(0) = 0$.
Q: What is the difference between sine and cosine graphs?
A: The cosine graph is the same shape as sine, but shifted left by $\frac{\pi}{2}$. In fact, $\cos(x) = \sin(x + \frac{\pi}{2})$. Cosine starts at its maximum (1) while sine starts at 0.
Q: How do I graph negative amplitude like $y = -2\sin(x)$?
A: A negative amplitude reflects the graph across the x-axis. The wave that normally goes up first now goes down first. The peaks and troughs are inverted.
Graphing the Sine Function
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Graphing the Sine Function
Learn to graph the sine function and understand its key properties like amplitude, period, and phase.